Cash project takeaways

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#include <stdio.h>
#include <cs50.h>

int entercents(void);
int count25(int b);
int remainingafter25(int b);
int count10(int b);
int remainingafter10(int b);
int count5(int b);
int remainingafter5(int b);
int count1(int b);

int main(void)
{
    int b = entercents();
    printf("result is %i\n", b);

    int c25 = count25(b);
    printf("count25 is%i", c25);

    int r25 = remainingafter25(b);
    printf("remaining after 25count is %i", r25);

    b = r25;

    int c10 = count10(b);
    printf("count10 is %i", c10);

    int r10 = remainingafter10(b);
    printf("remaining after 10count is %i", r10);

    b = r10;
    int c5 = count5(b);
    printf("count5 is %i", c5);

    int r5 = remainingafter5(b);
    printf("remaining after 5count is %i", r5);

    b = r5;
    int c1 = count1(b);
    printf("count1 is %i", c1);

    int totalcoins = c25 + c10 + c5 + c1;
    printf("totalcoins %i", totalcoins);

}

int entercents(void)

{
    int d;
    do
    {
        d = get_int("enter cents");
    }

    while (d < 0);
    return d;
}

int count25(int b)
{
    int x = b / 25;
    return x;
}

int remainingafter25(int b)
{
    int x = b % 25;
    return x;
}

int count10(int b)
{
    int x = b / 10;
    return x;
}

int remainingafter10(int b)
{
    int x = b % 10;
    return x;
}

int count5(int b)
{
    int x = b / 5;
    return x;
}

int remainingafter5(int b)
{
    int x = b % 5;
    return x;
}

int count1(int b)
{
    int x = b / 1;
    return x;
}

			

Cash project will help learn creating functions in C. Once you execute the function for 25 cents successfully, replicate the same for 10, 5, and 1 cents. For 1 cents, there is no need to apply division and modulus operator (though I have applied this to maintain uniformity) as say remaining cents after 5 cents is 4 cents. So 4 cents will be the count of the number of coins.

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