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CS50x threads to aide as a supplementary resource › Forums › CS50’s Introduction to Computer Science by Harvard University on Edx › Week 2: [Arrays] – Functions, Variable and Scope, Debugging, Arrays, and Command Line Arguments › Char type while counting number of words in Readability project
Tagged: char type
#include
#include
#include
int main(void)
{
string enterword = get_string("input: ");
int t = strlen(enterword);
printf("%i\n", t);
int counter = 0;
for(int i = 0; i<= t; i++)
{
if (enterword == '.'|| enterword == '!' || enterword == '?'){
counter = counter + 1;}
}
printf("number of lines %i\n",counter);
int wordcounter = 0;
for (int i = 0; i<= t; i++)
{
if (enterword == ' ' || enterword == '.'){
wordcounter = wordcounter + 1;
}
}
printf("total words %i\n", wordcounter);
}
The above program fails to calculate correctly no. of words. The problem is that char type can take only one character.
int wordcounter = 0;
for (int i = 0; i<= t; i++)
{
if (enterword == ' ' || enterword == '.'){
wordcounter = wordcounter + 1;
}
}
printf("total words %i\n", wordcounter);
I cannot have enterword == ‘. ‘; that is, one space after. to count correctly number of words when before full stop and a new line starts with a space after that full stop. Seeking help how to approach in such scenario.
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